document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=386670>Question 386670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A card is selected from an ordinary deck of 52 cards.Find the probabilities for each of the following:a. <BR>\n" );
document.write( "A red card                    <BR>\n" );
document.write( "b. A face card<BR>\n" );
document.write( "c. A red card or a 10            <BR>\n" );
document.write( "d. A queen<BR>\n" );
document.write( "e. Not a queen                   <BR>\n" );
document.write( "f. A face card or a club<BR>\n" );
document.write( "g. A face card and a club       <BR>\n" );
document.write( " h. Not a face card and not a club </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275702 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a. 1/2\r<BR>\n" );
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document.write( "b. 12/52, or 3/13.\r<BR>\n" );
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document.write( "c.  1/2 + 4/52 - 2/52 = 1/2 + 2/52 = 1/2 + 1/26 = 14/26 = 7/13.\r<BR>\n" );
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document.write( "d. 4/52, or 1/13\r<BR>\n" );
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document.write( "e.  1-1/13 = 12/13\r<BR>\n" );
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document.write( "f.  3/13 + 13/52 - 3/52 = 3/13 + 10/52 = 3/13 + 5/26 = 11/26\r<BR>\n" );
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document.write( "g.  3/52\r<BR>\n" );
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document.write( "h. (52 - 12 - 10)/52 = 30/52 = 15/26 </SPAN>\n" );
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