document.write( "Question 389143: write an equation in standard form with roots -4,10 \n" ); document.write( "

Algebra.Com's Answer #275681 by nerdybill(7384) $\"\"$ $\"About$

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For a quadratic to have -4,10 as roots then it must have the following factors:
\n" ); document.write( "(x+4)(x-10)
\n" ); document.write( "FOIL the above:
\n" ); document.write( "x^2 -10x + 4x - 40
\n" ); document.write( "x^2 -6x - 40
\n" ); document.write( ".
\n" ); document.write( "putting it in standard form:
\n" ); document.write( "x^2 -6x - 40=0
\n" ); document.write( "(x^2 -6x +9) = 40 + 9
\n" ); document.write( "(x-3)^2 = 49
\n" ); document.write( "f(x) = (x-3)^2 -49\r
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