document.write( "Question 389116: Find the dimensions of a rectangle with an area of sixty square feet and a diagonal of thirteen feet. \n" ); document.write( "
Algebra.Com's Answer #275644 by edjones(8007)\"\" \"About 
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Let the length=a and the width=b
\n" ); document.write( "ab=60
\n" ); document.write( "a=60/b
\n" ); document.write( "a^2+b^2=13^2
\n" ); document.write( "(60/b)^2+b^2=169 Substitute 60/b for a
\n" ); document.write( "3600/b^2 + b^2 = 169
\n" ); document.write( "3600+b^4=169b^2 multiply each side by b^2\r
\n" ); document.write( "\n" ); document.write( "b^4-169b^2+3600=0
\n" ); document.write( "(b^2-144)(b^2-25)=0
\n" ); document.write( "(b+12)(b-12)(b+5)(b-5)=0
\n" ); document.write( "b=5', a=12'
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