document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389132>Question 389132</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A principal of $2400.00 is invested at 8% interest, compounded annually. How many years will it take to accumulate $7000.00 or more in the account? \r<BR>\n" );
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document.write( "Write the answer as a whole number.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275642 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275642\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 7000 = 2400*(1.08)^n (n in years)<BR>\n" );
document.write( "1.08^n = 7000/2400<BR>\n" );
document.write( "n*log(1.08) = log(70/24)<BR>\n" );
document.write( "n = log(70/24)/log(1.08)<BR>\n" );
document.write( "n =~ 14 years<BR>\n" );
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