document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42403>Question 42403</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question with logarithms: Hi I'm wondering something about logarithms. I have this equation to prove which looks like this: b ^ log_b (x) = x Where ^ means exponent and _ means subscript.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27564 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yes...what that shows you is that exponentiating to the base b and taking the log to the base b (where b>0) are inverse operations...that is, they undo each other...<BR>\n" );
document.write( "If you take the log of both sides you get<BR>\n" );
document.write( "b ^ log_b (x) = x<BR>\n" );
document.write( "log_b(b ^ log_b (x)) = log_b (x)<BR>\n" );
document.write( "log_b (x) = log_b (x) </SPAN>\n" );
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