document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389117>Question 389117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the base of a 40 inch high cone is 12 inches in diameter, what is the volume of the cone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275630 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275630\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> V=(pir^2h)/3<BR>\n" );
document.write( "V=3.14*6^2*40/3<BR>\n" );
document.write( "V=4521.6/3<BR>\n" );
document.write( "V=1507.2 cu in </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );