document.write( "Question 389084: A cattle train left Miami and traveled toward New York. 14 hours later a diesel train left traveling at 45 km/h in an effort to catch up to the cattle train. After traveling for four hours the diesel train finally caught up. What was the cattle train's average speed? \n" ); document.write( "
Algebra.Com's Answer #275629 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! speed = distance ÷ time \n" ); document.write( "time cattle train took = 14 hours before the diesel train left plus the 4 hours the diesel train took to catch up. \n" ); document.write( "distance = 4 hours * 45 km/hour (diesel train traveled to catch up\r \n" ); document.write( "\n" ); document.write( "average speed of cattle train = 4*45/(14+4)=10 km/hr \n" ); document.write( " |