document.write( "Question 387782: A speedboat takes 4 hours longer to go 80 miles up a river than to return. If the boat cruises at 15 miles per hour in still water, what is the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #275599 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Rate*Time=Distance \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Let the current speed be C. \n" ); document.write( "With the current, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Against the current, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Subsituting, \n" ); document.write( " \n" ); document.write( "Use the common denominator, \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Only one solution since \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |