document.write( "Question 386664: Please assist, \r
\n" ); document.write( "\n" ); document.write( "4x-y=16
\n" ); document.write( "x+6y=29\r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #275569 by gwendolyn(128)\"\" \"About 
You can put this solution on YOUR website!
The second equation states:
\n" ); document.write( "x+6y=29
\n" ); document.write( "We can manipulate this equation to find x in terms of y by subtracting 6y from both sides of the equation:
\n" ); document.write( "x+6y=29
\n" ); document.write( "x+6y-6y=29-6y
\n" ); document.write( "x=29-6y
\n" ); document.write( "We can substitute this value for x into the first equation in the problem.
\n" ); document.write( "4x-y=16
\n" ); document.write( "4(29-6y)-y=16
\n" ); document.write( "Next, we can distribute the 4 over the first set of parentheses.
\n" ); document.write( "116-24y-y=16
\n" ); document.write( "116-25y=16
\n" ); document.write( "After that, we can subtract 116 from both sides of the equation.
\n" ); document.write( "-25y=-100
\n" ); document.write( "Finally, we divide both sides of the equation by negative 25 to isolate our variable.
\n" ); document.write( "y=4
\n" ); document.write( "All that we need to do now is find the value of x:
\n" ); document.write( "x=29-6y
\n" ); document.write( "x=29-24
\n" ); document.write( "x=5
\n" ); document.write( "So, y=4 and x=5
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