document.write( "Question 386664: Please assist, \r
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document.write( "4x-y=16
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document.write( "x+6y=29\r
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document.write( "Thank you! \n" );
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Algebra.Com's Answer #275569 by gwendolyn(128)![]() ![]() You can put this solution on YOUR website! The second equation states: \n" ); document.write( "x+6y=29 \n" ); document.write( "We can manipulate this equation to find x in terms of y by subtracting 6y from both sides of the equation: \n" ); document.write( "x+6y=29 \n" ); document.write( "x+6y-6y=29-6y \n" ); document.write( "x=29-6y \n" ); document.write( "We can substitute this value for x into the first equation in the problem. \n" ); document.write( "4x-y=16 \n" ); document.write( "4(29-6y)-y=16 \n" ); document.write( "Next, we can distribute the 4 over the first set of parentheses. \n" ); document.write( "116-24y-y=16 \n" ); document.write( "116-25y=16 \n" ); document.write( "After that, we can subtract 116 from both sides of the equation. \n" ); document.write( "-25y=-100 \n" ); document.write( "Finally, we divide both sides of the equation by negative 25 to isolate our variable. \n" ); document.write( "y=4 \n" ); document.write( "All that we need to do now is find the value of x: \n" ); document.write( "x=29-6y \n" ); document.write( "x=29-24 \n" ); document.write( "x=5 \n" ); document.write( "So, y=4 and x=5 \n" ); document.write( " |