document.write( "Question 387664: An express train travels 150 km in the same time that a freight train travels 100 km. If the express train goes 20km per hour faster than the freight train, find the rate of each. Tnx! \n" ); document.write( "
Algebra.Com's Answer #275556 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Rate*Time=Distance
\n" ); document.write( "\"R%2At=D\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"R%5Be%5D%2At=150\"
\n" ); document.write( "\"t=150%2FR%5Be%5D\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"R%5Bf%5D%2At=100\"
\n" ); document.write( "\"t=100%2FR%5Bf%5D\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"150%2FR%5Be%5D=100%2FR%5Bf%5D\"
\n" ); document.write( "\"100R%5Be%5D=150R%5Bf%5D\"
\n" ); document.write( "\"R%5Be%5D=%28150%2F100%29R%5Bf%5D\"
\n" ); document.write( "\"R%5Be%5D=%283%2F2%29R%5Bf%5D\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"R%5Be%5D=R%5Bf%5D%2B20\"
\n" ); document.write( "Substitute,
\n" ); document.write( "\"%283%2F2%29R%5Bf%5D=R%5Bf%5D%2B20\"
\n" ); document.write( "\"%281%2F2%29R%5Bf%5D=20\"
\n" ); document.write( "\"highlight%28R%5Bf%5D=40%29\"kph
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"R%5Be%5D=%283%2F2%29%2840%29\"
\n" ); document.write( "\"highlight%28R%5Be%5D=60%29\"kph
\n" ); document.write( "
\n" );