document.write( "Question 389027: the denominator of the fraction is 2 more than the numerator. if 1 is subtracted from both numerator and denominator, the resulting fraction has a value of 1/2. find the original fraction
\n" ); document.write( ". Be specific in explaining please? \n" ); document.write( "

Algebra.Com's Answer #275527 by Fombitz(32388) $\"\"$ $\"About$

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Originally, the fraction was,
\n" ); document.write( " $\"X%2F%28X%2B2%29\"$
\n" ); document.write( "Subtracting 1 from the numerator and denominator gives,
\n" ); document.write( " $\"%28X-1%29%2F%28X%2B2-1%29=1%2F2\"$
\n" ); document.write( " $\"%28X-1%29%2F%28X%2B1%29=1%2F2\"$
\n" ); document.write( " $\"2%28X-1%29=X%2B1\"$
\n" ); document.write( " $\"2X-2=X%2B1\"$
\n" ); document.write( " $\"X=3\"$
\n" ); document.write( "So the original fraction was,
\n" ); document.write( " $\"X%2F%28X%2B2%29=3%2F%283%2B2%29\"$
\n" ); document.write( " $\"highlight%28X%2F%28X%2B2%29=3%2F5%29\"$
\n" ); document.write( " \n" ); document.write( "

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