document.write( "Question 389043: The line through A(3,1) perpendicular to x - 4y = 8 meets the x-axis at P and the y-axis at Q. Calculate the ratio PA : AQ. \n" ); document.write( "

Algebra.Com's Answer #275519 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Note: the standard slope-intercept form for an equation of a line is y = mx + b  
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document.write( "where m is the slope and b the y-intercept.  
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document.write( "line through A(3,1) perpendicular to x - 4y = 8 OR y = (1/4)x - 2  
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document.write( "Perpendicular lines have slopes that are negative reciprocals of one another
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document.write( "New line y = -4x + b using ordered pair Pt(3,1) to solve for b
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document.write( "         1 = -12 + b     b = 13
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document.write( "         y = -4x + 13   P(13/4,0) and Q(0,13)on this line
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document.write( "Calculate the ratio PA : AQ
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document.write( "PA Distance would be: P(13/4,0)and A(3,1)
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document.write( "PA = 
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document.write( "AQ Distance would be: A(3,1)and Q(0,13)
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document.write( "AQ =  
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document.write( "PA:AQ would be   1.031:12.369
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