document.write( "Question 389037: The line y = ax + 7 is parallel to the line y = 2x - 3. The line y = bx + 7 is perpendicular to the line y = 2x- 3.
\n" ); document.write( "a) State the value of a and of b.
\n" ); document.write( "b) Calculate the perpendicular distance between the pair of parallel lines.\r
\n" ); document.write( "\n" ); document.write( "*Please solve this question and explain it in detail. Also explain your answers in as much detail as possible, especially part (b). Thanks :)*
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Algebra.Com's Answer #275516 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi,
\n" ); document.write( "Note: the standard slope-intercept form for an equation of a line is y = mx + b
\n" ); document.write( "where m is the slope and b the y-intercept.
\n" ); document.write( "a) State the value of a and of b.
\n" ); document.write( "y = ax + 7 is parallel to the line y = 2x - 3 (lines have same slope)
\n" ); document.write( " a = 2 y = 2x + 7
\n" ); document.write( "The line y = bx + 7 is perpendicular to the line y = 2x- 3.
\n" ); document.write( "Perpendicular lines have Slopes that are negative reciprocals of one another:
\n" ); document.write( " b = -1/2 y = -.5x + 7
\n" ); document.write( "b) Calculate the perpendicular distance between the pair of parallel lines.
\n" ); document.write( "graphing
\n" ); document.write( "y = 2x - 3 and y = 2x + 7 and the line perpendicular to both: y = -.5x + 7
\n" ); document.write( "Distance between Pt(0,7) and Pt(4,5)would be:
\n" ); document.write( "\"sqrt%28%28x%5B2%5D+-+x%5B1%5D%29%5E2+%2B+%28y%5B2%5D+-+y%5B1%5D%29%5E2%29\"
\n" ); document.write( "\"sqrt%28%284+-+0%29%5E2+%2B+%285+-+7%29%5E2%29\"
\n" ); document.write( "\"sqrt%28%284+-+0%29%5E2+%2B+%285+-+6%29%5E2%29\"
\n" ); document.write( "\"sqrt%28%284%29%5E2+%2B+%28-2%29%5E2%29\"
\n" ); document.write( "\"sqrt%2820%29=+highlight%284.472%29\"
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