document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42286>Question 42286</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you hlep me figure this out?\r<BR>\n" );
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document.write( "Mark uses 1pt 9 fl oz and then 2 pt 10 fl oz from a container of film developer that holds 3qt. How much of the developer remains? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27549 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27549\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay...let's add what he used and then subtract that from the 3 qts for our answer...so<BR>\n" );
document.write( "1 pt 9 oz + 2 pt 10 oz =<BR>\n" );
document.write( "3 pt 19 oz =<BR>\n" );
document.write( "4 pt 3 oz =<BR>\n" );
document.write( "2 qt 0 pt 3 oz<BR>\n" );
document.write( "Now if we subtract that from 3 quarts, we get<BR>\n" );
document.write( "3 qt - 2 qt 0 pt 3 oz =<BR>\n" );
document.write( "2 qt 2 pt - 2 qt 0 pt 3 oz =<BR>\n" );
document.write( "2 qt 1 pt 16 oz - 2 qt 0 pt 3 oz =<BR>\n" );
document.write( "1 pt 13 oz </SPAN>\n" );
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