document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=389000>Question 389000</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem.\r<BR>\n" );
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document.write( "Find the solutions for x, y, and z: \r<BR>\n" );
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document.write( "x + 2y - z = 5 <BR>\n" );
document.write( "2x + y + z = 1 <BR>\n" );
document.write( "x - y + z = -1 <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275478 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275478\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+2y-z=5,2x+y+z=1,x-y+z=-1\r<BR>\n" );
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document.write( "Move all terms not containing x to the right-hand side of the equation.<BR>\n" );
document.write( "x=-2y+z+5_2x+y+z=1_x-y+z=-1\r<BR>\n" );
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document.write( "Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is -2y+z+5.<BR>\n" );
document.write( "x=-2y+z+5_2(-2y+z+5)+y+z=1_x-y+z=-1\r<BR>\n" );
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document.write( "Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is -2y+z+5.<BR>\n" );
document.write( "x=-2y+z+5_2(-2y+z+5)+y+z=1_(-2y+z+5)-y+z=-1\r<BR>\n" );
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document.write( "Multiply 2 by each term inside the parentheses.<BR>\n" );
document.write( "x=-2y+z+5_-4y+2z+10+y+z=1_(-2y+z+5)-y+z=-1\r<BR>\n" );
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document.write( "Since -4y and y are like terms, subtract y from -4y to get -3y.<BR>\n" );
document.write( "x=-2y+z+5_-3y+2z+10+z=1_(-2y+z+5)-y+z=-1\r<BR>\n" );
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document.write( "Since 2z and z are like terms, add z to 2z to get 3z.<BR>\n" );
document.write( "x=-2y+z+5_-3y+3z+10=1_(-2y+z+5)-y+z=-1\r<BR>\n" );
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document.write( "Remove the parentheses around the expression -2y+z+5.<BR>\n" );
document.write( "x=-2y+z+5_-3y+3z+10=1_-2y+z+5-y+z=-1\r<BR>\n" );
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document.write( "Since -2y and -y are like terms, subtract y from -2y to get -3y.<BR>\n" );
document.write( "x=-2y+z+5_-3y+3z+10=1_-3y+z+5+z=-1\r<BR>\n" );
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document.write( "Since z and z are like terms, add z to z to get 2z.<BR>\n" );
document.write( "x=-2y+z+5_-3y+3z+10=1_-3y+2z+5=-1\r<BR>\n" );
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document.write( "Move all terms not containing y to the right-hand side of the equation.<BR>\n" );
document.write( "x=-2y+z+5_-3y=-3z-10+1_-3y+2z+5=-1\r<BR>\n" );
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document.write( "Add 1 to -10 to get -9.<BR>\n" );
document.write( "x=-2y+z+5_-3y=-3z-9_-3y+2z+5=-1\r<BR>\n" );
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document.write( "Divide each term in the equation by -3.<BR>\n" );
document.write( "x=-2y+z+5_-(3y)/(-3)=-(3z)/(-3)-(9)/(-3)_-3y+2z+5=-1\r<BR>\n" );
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document.write( "Simplify the left-hand side of the equation by canceling the common factors.<BR>\n" );
document.write( "x=-2y+z+5_y=-(3z)/(-3)-(9)/(-3)_-3y+2z+5=-1\r<BR>\n" );
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document.write( "Simplify the right-hand side of the equation by simplifying each term.<BR>\n" );
document.write( "x=-2y+z+5_y=z+3_-3y+2z+5=-1\r<BR>\n" );
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document.write( "Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is z+3.<BR>\n" );
document.write( "x=-2y+z+5_y=z+3_-3(z+3)+2z+5=-1\r<BR>\n" );
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document.write( "Multiply -3 by each term inside the parentheses.<BR>\n" );
document.write( "x=-2y+z+5_y=z+3_-3z-9+2z+5=-1\r<BR>\n" );
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document.write( "Since -3z and 2z are like terms, subtract 2z from -3z to get -z.<BR>\n" );
document.write( "x=-2y+z+5_y=z+3_-z-9+5=-1\r<BR>\n" );
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document.write( "Add 5 to -9 to get -4.<BR>\n" );
document.write( "x=-2y+z+5_y=z+3_-z-4=-1\r<BR>\n" );
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document.write( "Since -4 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 4 to both sides.<BR>\n" );
document.write( "x=-2y+z+5_y=z+3_-z=4-1\r<BR>\n" );
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document.write( "Subtract 1 from 4 to get 3.<BR>\n" );
document.write( "x=-2y+z+5_y=z+3_-z=3\r<BR>\n" );
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document.write( "Multiply each term in the equation by -1.<BR>\n" );
document.write( "x=-2y+z+5_y=z+3_-z*-1=3*-1\r<BR>\n" );
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document.write( "Multiply -z by -1 to get z.<BR>\n" );
document.write( "x=-2y+z+5_y=z+3_z=3*-1\r<BR>\n" );
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document.write( "Multiply 3 by -1 to get -3.<BR>\n" );
document.write( "x=-2y+z+5_y=z+3_z=-3\r<BR>\n" );
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document.write( "Replace all occurrences of z with the solution found by solving the last equation for z.  In this case, the value substituted is -3.<BR>\n" );
document.write( "x=-2y+(-3)+5_y=z+3_z=-3\r<BR>\n" );
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document.write( "Replace all occurrences of z with the solution found by solving the last equation for z.  In this case, the value substituted is -3.<BR>\n" );
document.write( "x=-2y+(-3)+5_y=(-3)+3_z=-3\r<BR>\n" );
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document.write( "Remove the parentheses around the expression -3.<BR>\n" );
document.write( "x=-2y-3+5_y=(-3)+3_z=-3\r<BR>\n" );
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document.write( "Add 5 to -3 to get 2.<BR>\n" );
document.write( "x=-2y+2_y=(-3)+3_z=-3\r<BR>\n" );
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document.write( "Remove the parentheses around the expression -3.<BR>\n" );
document.write( "x=-2y+2_y=-3+3_z=-3\r<BR>\n" );
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document.write( "Add 3 to -3 to get 0.<BR>\n" );
document.write( "x=-2y+2_y=0_z=-3\r<BR>\n" );
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document.write( "Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is 0.<BR>\n" );
document.write( "x=-2(0)+2_y=0_z=-3\r<BR>\n" );
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document.write( "Multiply -2 by each term inside the parentheses.<BR>\n" );
document.write( "x=0+2_y=0_z=-3\r<BR>\n" );
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document.write( "Remove the 0 from the polynomial; adding or subtracting 0 does not change the value of the expression.<BR>\n" );
document.write( "x=2_y=0_z=-3\r<BR>\n" );
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document.write( "This is the solution to the system of equations.<BR>\n" );
document.write( "x=2_y=0_z=-3 </SPAN>\n" );
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