document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388997>Question 388997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 27. One half of the first number plus one third of the second number is 11. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275466 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose the two numbers are x and y. Then, x+y = 27. From the second statement,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F2+%2B+y%2F3+=+11 ALIGN=MIDDLE  ALT=\"x%2F2+%2B+y%2F3+=+11\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Multiply the previous equation by 6 to clear the fractions (it makes life much easier...)\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x+%2B+2y+=+66 ALIGN=MIDDLE  ALT=\"3x+%2B+2y+=+66\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Rewrite 3x + 2y as x + 2x + 2y (so we can use substitution)\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+2x+%2B+2y+=+66 ALIGN=MIDDLE  ALT=\"x+%2B+2x+%2B+2y+=+66\"   DISABLED_style= \"max-width:90%; height:auto;\" > Since 2x + 2y = 54,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+54+=+66 ALIGN=MIDDLE  ALT=\"x+%2B+54+=+66\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "x = 12. Substituting into the very first equation, we get y = 15. </SPAN>\n" );
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