document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388997>Question 388997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 27. One half of the first number plus one third of the second number is 11. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275465 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275465\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 27. One half of the first number plus one third of the second number is 11. Find the numbers.<BR>\n" );
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document.write( "let the numbers be x & y<BR>\n" );
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document.write( "x+y =27..............1<BR>\n" );
document.write( "x/2 + y/3 = 11<BR>\n" );
document.write( "LCD = 6<BR>\n" );
document.write( "multiply by 6<BR>\n" );
document.write( "3x+2y=66.............2<BR>\n" );
document.write( "multiply (1) by -3<BR>\n" );
document.write( "-3x-3y=-81<BR>\n" );
document.write( "add this to (2)<BR>\n" );
document.write( "-3x+3x-3y+2y=-81+66<BR>\n" );
document.write( "-y=-15<BR>\n" );
document.write( "y=15<BR>\n" );
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document.write( "plug y in (1)<BR>\n" );
document.write( "x=12<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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