document.write( "Question 388994: Jeff is Three times as old as his son. In nine years, Jeff will be twice as old as his son. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #275449 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Jeff is Three times as old as his son. In nine years, Jeff will be twice as old as his son. How old is each now?\r \n" ); document.write( "\n" ); document.write( "Let son's age = x \n" ); document.write( "Jeff age = 3x \n" ); document.write( ".. \n" ); document.write( "after 9 years \n" ); document.write( "son = x+9 years \n" ); document.write( "Jeff = 3x+9 years \n" ); document.write( ".. \n" ); document.write( "3x+9=2(x+9) \n" ); document.write( ".. \n" ); document.write( "3x+9 = 2x+18 \n" ); document.write( "-2x \n" ); document.write( "3x-2x+9 = 18 \n" ); document.write( "x+9=18 \n" ); document.write( "-9 \n" ); document.write( "x=18-9 \n" ); document.write( "x=9... Son's age \n" ); document.write( "Jeff's age = 3x = 27 years \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |