document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388968>Question 388968</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using long division, please solve x^2 + 7x + 10 divided by x + 3   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275426 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275426\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%5E%282%29%2B7x%2B10%29%2F%28x%2B3%29 ALIGN=MIDDLE  ALT=\"%28x%5E%282%29%2B7x%2B10%29%2F%28x%2B3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  <BR>\n" );
document.write( "     <BR>\n" );
document.write( "     x +4<BR>\n" );
document.write( "     ___________<BR>\n" );
document.write( "x+3/x^(2)+7x+10<BR>\n" );
document.write( "***-x^(2)-3x<BR>\n" );
document.write( "****---------<BR>\n" );
document.write( "***********4x+10<BR>\n" );
document.write( "***********-4x-12<BR>\n" );
document.write( "***********------<BR>\n" );
document.write( "***************-2\r<BR>\n" );
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document.write( " (The final answer is the quotient plus the remainder over the divisor)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B4-%282%29%2F%28x%2B3%29 ALIGN=MIDDLE  ALT=\"x%2B4-%282%29%2F%28x%2B3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "doing more work to further the answer of x+4  :\r<BR>\n" );
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document.write( "x+4-(2)/(x+3)\r<BR>\n" );
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document.write( "Multiply each term by a factor of 1 that will equate all the denominators.  In this case, all terms need a denominator of (x+3).<BR>\n" );
document.write( "x*(x+3)/(x+3)+4*(x+3)/(x+3)-(2)/(x+3)\r<BR>\n" );
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document.write( "Multiply the expression by a factor of 1 to create the least common denominator (LCD) of (x+3).<BR>\n" );
document.write( "(x(x+3))/(x+3)+4*(x+3)/(x+3)-(2)/(x+3)\r<BR>\n" );
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document.write( "Multiply the expression by a factor of 1 to create the least common denominator (LCD) of (x+3).<BR>\n" );
document.write( "(x(x+3))/(x+3)+(4(x+3))/(x+3)-(2)/(x+3)\r<BR>\n" );
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document.write( "The numerators of expressions that have equal denominators can be combined.  In this case, (x(x+3))/((x+3)) and ((4(x+3)))/((x+3)) have the same denominator of (x+3), so the numerators can be combined.<BR>\n" );
document.write( "(x(x+3)+(4(x+3))-2)/(x+3)\r<BR>\n" );
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document.write( "Simplify the numerator of the expression.<BR>\n" );
document.write( "(x^(2)+3x+4x+12-2)/(x+3)\r<BR>\n" );
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document.write( "Combine all similar terms in the polynomial x^(2)+3x+4x+12-2.<BR>\n" );
document.write( "(x^(2)+7x+10)/(x+3)\r<BR>\n" );
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document.write( "In this problem 5*2=10 and 5+2=7, so insert 5 as the right hand term of one factor and 2 as the right-hand term of the other factor.<BR>\n" );
document.write( "((x+5)(x+2))/(x+3)\r<BR>\n" );
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document.write( "Yet; your origional, long division answer= x+4 (ignore the ***'s)<BR>\n" );
document.write( "I had to put them there to show you the work on an even scale.\r<BR>\n" );
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document.write( "       \r<BR>\n" );
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document.write( " </SPAN>\n" );
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