document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388807>Question 388807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In an examination 70% of the candidates passed in English, 65% in mathematics, 27% failed in both the subjects. Find the probability that a student selected at random has passed in both the subjects  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275327 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275327\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To understand this a Venn diagram should be used.<BR>\n" );
document.write( ".70+.65+.27=1.62<BR>\n" );
document.write( "Since the probability of passing E only + M only + both E & M + neither E nor M must add up to 1 then P(EnM)=.62 ANSWER<BR>\n" );
document.write( "(P(E)=.08 + P(M)=.03 + P(EnM)=.62 + P(EnM)'=.27) = 1.00<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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