document.write( "Question 388893: Ahmad and Ushna start off simultaneously from two towns to meet one another. If Ahmad travels 2 km/h faster than Ushna; they would meet in 3 hours. If Ushna travels 1 km/h slower and Ahmad's speed is two-thirds of his previous speed, they would meet in 4 hours. How far apart are the two towns? \n" ); document.write( "
Algebra.Com's Answer #275300 by mananth(16946)\"\" \"About 
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Ahmad travels 2 km/h faster than Ushna; they would meet in 3 hours. If Ushna travels 1 km/h slower and Ahmad's speed is two-thirds of his previous speed, they would meet in 4 hours. How far apart are the two towns?
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\n" ); document.write( "Ushna --- speed = x km/h
\n" ); document.write( "Ahmad x+2 km/h
\n" ); document.write( "..
\n" ); document.write( "combined speed = x+x+2 = 2x+2 km/h
\n" ); document.write( "..
\n" ); document.write( "D= speed * time
\n" ); document.write( "D= 3*(2x+2)
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\n" ); document.write( "Ushna (x-1)
\n" ); document.write( "Ahmad 2/3(x+2)
\n" ); document.write( "combined speed = 2/3(x+2)+(x-1)
\n" ); document.write( "combined speed = 2x/3 + 4/3 +x-1
\n" ); document.write( "combined speed = 5x/3 +1/3
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\n" ); document.write( "D= 4*(5x/3+1/3)
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\n" ); document.write( "4*(5x/3+1/3)=3(2x+2)
\n" ); document.write( "20x/3+4/3 = 6x+6
\n" ); document.write( "20x/3-6x=6-4/3
\n" ); document.write( "(20x-18x)/3=14/3
\n" ); document.write( "2x=14
\n" ); document.write( "2x=14
\n" ); document.write( "x= 7 km/h Ushna's speed.
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\n" ); document.write( "D= 3(2x+2)
\n" ); document.write( "D=3(14+2)
\n" ); document.write( "D= 48 km. Distance between two towns
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\n" ); document.write( "m.ananth@hotmail.ca
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