document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388874>Question 388874</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A shopkeeper bought some eggs at 15 cents each. Six of them were broken while the rest were sold at 20 cents each. If she made a profit of $4.80, find how many eggs she bought. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275282 by </B><A HREF=/tutors/aboutme.mpl?userid=haileytucki><B>haileytucki(390)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=haileytucki><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=haileytucki><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275282\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, we know that 6 time 15 (the ones broken) = .90 cents.<BR>\n" );
document.write( "If she made a profit of 4.80, you have to add the loss of 90cents,<BR>\n" );
document.write( "equaling, 5.70 cents.<BR>\n" );
document.write( "Now, a little algebra:\r<BR>\n" );
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document.write( ".20x =4.80\r<BR>\n" );
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document.write( "0.2x=4.8\r<BR>\n" );
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document.write( "Divide each term in the equation by 0.2.<BR>\n" );
document.write( "(0.2x)/(0.2)=(4.8)/(0.2)\r<BR>\n" );
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document.write( "Cancel the common factor of 0.2.<BR>\n" );
document.write( "x=(4.8)/(0.2)\r<BR>\n" );
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document.write( "Divide 4.8 by 0.2 to get 24.<BR>\n" );
document.write( "x=24 are the ones she sold at 20 cent apiece;<BR>\n" );
document.write( "you add the 6 she broke= 30 eggs </SPAN>\n" );
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