document.write( "Question 388841: 5) Solve for all values of 2 sin θ + sqrt 3=0 when 0° ≤ θ ≤ 360°.\r
\n" ); document.write( "\n" ); document.write( "a)240°, 300° b)150°, 210° c)60°, 120° d)60°, 300°\r
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Algebra.Com's Answer #275263 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"2sin%28theta%29+%2B+sqrt%283%29=0\" when \"%220%B0%22+%3C=+theta+%3C+%22360%B0%22\"\r\n" );
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document.write( "\"2sin%28theta%29+%2B+sqrt%283%29=0\"\r\n" );
document.write( "\"2sin%28theta%29+=-sqrt%283%29\"\r\n" );
document.write( "\"sin%28theta%29+=+-sqrt%283%29%2F2\"\r\n" );
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document.write( "We know that \"sin%28%2260%B0%22%29+=+%22%22%2Bsqrt%283%29%2F2\", not \"-sqrt%283%29%2F2\"\r\n" );
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document.write( "but that tells us that the reference angle of q is 60°.\r\n" );
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document.write( "We also know that the sine is a negative number in the third and fourth\r\n" );
document.write( "quadrants.  To find the angle whose reference angle is 60° in the 3rd\r\n" );
document.write( "quadrant we add 180° to the reference angle 60°, and get 240°.  To find the\r\n" );
document.write( "angle whose reference angle is 60° in the 4th quadrant we subtract the\r\n" );
document.write( "reference angle 60° from 360° and get 300°.   \r\n" );
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document.write( "So yes you're right.\r\n" );
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document.write( "Edwin
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