document.write( "Question 388831: The length of a rectangle is 9 cm more than four times the width. If the perimeter of the rectangle is 58 cm, what are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #275236 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 9 cm more than four times the width. If the perimeter of the rectangle is 58 cm, what are its dimensions? \n" ); document.write( "--------------------- \n" ); document.write( "Let the width be \"x\": \n" ); document.write( "Then the length is \"4x+9\" \n" ); document.write( "----- \n" ); document.write( "Perimeter = 2(length + width) \n" ); document.write( "Solve: \n" ); document.write( "58 = 2(4x+9 + x) \n" ); document.write( "29 = 5x+9 \n" ); document.write( "5x = 20 \n" ); document.write( "x = 4 cm (width) \n" ); document.write( "4x+9 = 25 cm (length) \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |