document.write( "Question 388831: The length of a rectangle is 9 cm more than four times the width. If the perimeter of the rectangle is 58 cm, what are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #275236 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The length of a rectangle is 9 cm more than four times the width. If the perimeter of the rectangle is 58 cm, what are its dimensions?
\n" ); document.write( "---------------------
\n" ); document.write( "Let the width be \"x\":
\n" ); document.write( "Then the length is \"4x+9\"
\n" ); document.write( "-----
\n" ); document.write( "Perimeter = 2(length + width)
\n" ); document.write( "Solve:
\n" ); document.write( "58 = 2(4x+9 + x)
\n" ); document.write( "29 = 5x+9
\n" ); document.write( "5x = 20
\n" ); document.write( "x = 4 cm (width)
\n" ); document.write( "4x+9 = 25 cm (length)
\n" ); document.write( "=========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );