document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388802>Question 388802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A committee of 4 has to be selected from amongst 5 men and 4 women. In how many ways can this be done so as to include at least 1 man and 1 woman.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275214 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275214\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> # ways of choosing 1 man from 5 = 5C1 = 5.<BR>\n" );
document.write( "# ways of choosing 1 woman from 4 = 4C1 = 4.<BR>\n" );
document.write( "# ways of choosing 2 people from 7 remaining people = 7C2 = 21.<BR>\n" );
document.write( "By the fundamental principle of counting, the #ways of choosing 4 people so as to include at least 1 man and 1 woman is 5*4*21 = 420. </SPAN>\n" );
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