document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388802>Question 388802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A committee of 4 has to be selected from amongst 5 men and 4 women. In how many ways can this be done so as to include at least 1 man and 1 woman.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275210 by </B><A HREF=/tutors/aboutme.mpl?userid=Jk22><B>Jk22(389)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jk22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jk22><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Choosing 1 man and 1 woman gives 5*4 possibilities, <BR>\n" );
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document.write( "remain to choose 2 people out of 4+3=7 : 7*6<BR>\n" );
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document.write( "Since the order does not influence, this makes : <BR>\n" );
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document.write( "5*4*7*6/4! = 5*4*7*6/(4*3*2) = 35 possibilities </SPAN>\n" );
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