document.write( "Question 388778: How do I solve the following word problems:\r
\n" ); document.write( "\n" ); document.write( "1. If the population of a city is 178500 and it is growing at the rate of 2.1% per annum, in how many years will the population be 210000?\r
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Algebra.Com's Answer #275192 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
. If the population of a city is 178500 and it is growing at the rate of 2.1% per annum,
\n" ); document.write( " in how many years will the population be 210000?
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\n" ); document.write( "Let t = number of yrs to reach 210,000
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\n" ); document.write( "178500*1.021^t = 210000
\n" ); document.write( "Divide both sides by 178500
\n" ); document.write( "1.021^t = \"210000%2F178500\"
\n" ); document.write( "1.021^t = 1.17647
\n" ); document.write( "Use logs here
\n" ); document.write( "t*log(1.021) = log(1.17647)
\n" ); document.write( "t = \"log%281.17647%29%2Flog%281.021%29\"
\n" ); document.write( "t = 7.8 yrs
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\n" ); document.write( "Check solution on a calc: enter: 178500*1.021^7.8 ~ 210,000
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