document.write( "Question 388776: If $2500 is invested at a rate of 11% compounded continuously, find the balance in the account after 4 years. Use the formula A=Pe^rt.
\n" ); document.write( "a.3795.18 b.3881.77 c.4333.13 d.18472.64 \r
\n" ); document.write( "\n" ); document.write( "*the answers I'm getting do not match the answers above. please help.
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Algebra.Com's Answer #275182 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"A=Pe%5E%28rt%29\" Start with the continuous compounding formula.\r
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\n" ); document.write( "\n" ); document.write( "\"A=2500%2Ae%5E%280.11%2A4%29\" Plug in \"P=2500\", \"r=0.11\" (the decimal equivalent of 11%), and \"t=4\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=2500%2Ae%5E%280.44%29\" Multiply \"0.11\" and \"4\" to get \"0.44\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=2500%2A1.55270721851134\" Raise 'e' (which is approximately 2.71828) to the power \"0.44\" to get \"1.55270721851134\" (this value is approximate).\r
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\n" ); document.write( "\n" ); document.write( "\"A=3881.76804627834\" Multiply \"2500\" and \"1.55270721851134\" to get \"3881.76804627834\".\r
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\n" ); document.write( "\n" ); document.write( "\"A=3881.77\" Round to the nearest hundredth (ie to the nearest penny).\r
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\n" ); document.write( "\n" ); document.write( "So the balance after 4 years is $3,881.77\r
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\n" ); document.write( "\n" ); document.write( "So the answer is choice b)\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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