document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387153>Question 387153</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It takes jerry twice as long as sue to clean up the kitchen. if sure can clean up the kitchen in 1/3 hour, how long would it take to clean up the kitchen if she works together with jerry? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275178 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sue can clean the kitchen alone in 1/3 hr or 20 minutes<BR>\n" );
document.write( "jerry can clean the kitchen alone twice as long as sue =40 minutes<BR>\n" );
document.write( "working together they can clean the kitchen in x minutes\r<BR>\n" );
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document.write( "sue's rate + jerry rate = the rate both working together\r<BR>\n" );
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document.write( "1/20 +1/40 =1/x<BR>\n" );
document.write( "2/40 +1/40 =1/x<BR>\n" );
document.write( "3/40 =1/x<BR>\n" );
document.write( "x =40/3 =13.33 minutes\r<BR>\n" );
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document.write( "ans: working together sue and jerry can clean he kitchen in 13.33 minues </SPAN>\n" );
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