document.write( "Question 387349: a. The point on the x-axis that is equidistant (equal distance) from (8,4) and (-4,2)
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document.write( "b. The distance between the points (8,2) and (16,2). 8\r
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document.write( "c. The distance between the points (2,6) and (12,8).2\r
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document.write( "d. The midpoint between (8,2) and (10,6). \r
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document.write( "e. The midpoint between (-4, 2) and (-5, 3).
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Algebra.Com's Answer #275166 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! a. The point on the x-axis that is equidistant (equal distance) from (8,4) and (-4,2) \n" ); document.write( "The point will be (x,0) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "76 - 16x = 16 + 8x \n" ); document.write( "60 = 24x \n" ); document.write( "x = 2.5 \n" ); document.write( "---> (2.5,0) \n" ); document.write( "--------------- \n" ); document.write( "b. The distance between the points (8,2) and (16,2). 8 \n" ); document.write( "8 is right. \n" ); document.write( "----------- \n" ); document.write( "c. The distance between the points (2,6) and (12,8).2 \n" ); document.write( "How did you get 2? \n" ); document.write( " \n" ); document.write( "d=~ 10.198 units \n" ); document.write( "---------------- \n" ); document.write( "d. The midpoint between (8,2) and (10,6) \n" ); document.write( "Find the average of x and y separately \n" ); document.write( "x: (8 + 10)/2 = 0 \n" ); document.write( "y: (2 + 6)/2 = 4 \n" ); document.write( "--> (0,4) \n" ); document.write( "----------- \n" ); document.write( "e. The midpoint between (-4, 2) and (-5, 3) \n" ); document.write( "Same method as d --> (-4.5,2.5) \n" ); document.write( " \n" ); document.write( " |