document.write( "Question 388741: 
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document.write( "Walter and his parents are a little unusual. If he does an acceptable job of\r\n" );
document.write( "doing his chores ,he gets paid $3.33 fo that day. If he does an outstanding\r\n" );
document.write( "job, he gets paid $3 more. During one 10 day period, Walter received $42.30 for\r\n" );
document.write( "his work. How many days did he do an acceptable job?  How many days did he do\r\n" );
document.write( "an exceptional job?\r\n" );
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Algebra.Com's Answer #275153 by Edwin McCravy(20086)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let the number of days he does an acceptable job = x.\r\n" );
document.write( "then the number of days he does an outstanding job = 10-x\r\n" );
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document.write( "He got $3.33 for each of the x days, which amounted to $3.33x\r\n" );
document.write( "He got $3 more for each of the 10-x days, or $3.33+$3 or $6.33,\r\n" );
document.write( "which amounted to $6.33(10-x)\r\n" );
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document.write( "Get the equation from this:\r\n" );
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document.write( "(The money he got for all x days when he did an acceptable job) \r\n" );
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document.write( "                       PLUS\r\n" );
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document.write( "(The money he got for all 10-x days when he did an outstanding job)\r\n" );
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document.write( "                      EQUALS\r\n" );
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document.write( "                      $42.30\r\n" );
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document.write( "So the equation is\r\n" );
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document.write( "               $3.33x + $6.33(10 - x) = $42.30\r\n" );
document.write( "                 3.33x + 6.33(10 - x) =  42.30\r\n" );
document.write( "Drop the zero\r\n" );
document.write( "on 42.30, making \r\n" );
document.write( "it 42.3\r\n" );
document.write( "                 3.33x + 6.33(10 - x) =  42.3\r\n" );
document.write( "Distribute\r\n" );
document.write( "                 3.33x + 63.3 - 6.33x =  42.3\r\n" );
document.write( "combine x terms                  \r\n" );
document.write( "                        -3.00x + 63.3 =  42.3\r\n" );
document.write( "Drop the zeros\r\n" );
document.write( "on -3.00x, making\r\n" );
document.write( "it -3x\r\n" );
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document.write( "                           -3x + 63.3 =  42.3 \r\n" );
document.write( "subtract 63.3 \r\n" );
document.write( "from both sides:\r\n" );
document.write( "                                -63.3 = -63.3\r\n" );
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document.write( "                           -3x        = -21\r\n" );
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document.write( "Divide both sides by -3\r\n" );
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document.write( "                           -3x          -21\r\n" );
document.write( "                          -----       = ----\r\n" );
document.write( "                           -3            -3\r\n" );
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document.write( "Cancel the -3's on the\r\n" );
document.write( "left and divide on the\r\n" );
document.write( "right\r\n" );
document.write( "                             x        =   7            \r\n" );
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document.write( "The number of days he did an acceptable job = x = 7 days\r\n" );
document.write( "The number of days he did an outstanding job = 10-x = 10-7 = 3 days\r\n" );
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document.write( "Edwin
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