document.write( "Question 388748: Given that x and y are integers, solve x^2 + |y - 10| = 1 \n" ); document.write( "

Algebra.Com's Answer #275126 by jim_thompson5910(35256) $\"\"$ $\"About$

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The expression $\"x%5E2\"$ is ALWAYS positive. Also, $\"abs%28y-10%29\"$ is ALWAYS positive.\r
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\n" ); document.write( "\n" ); document.write( "Because of this, this means that BOTH $\"x%5E2\"$ and $\"abs%28y-10%29\"$ must be values less than 1. However, if x is an integer, this would mean that x must be zero (because any other integer would make $\"x%5E2%3E1\"$ ). So this leaves the equation $\"abs%28y-10%29=1\"$ . I'll let you solve it.\r
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\n" ); document.write( "\n" ); document.write( "Alternatively, we can let $\"abs%28y-10%29=0\"$ (using the same reasoning as above), which would leave us $\"x%5E2=1\"$ . Again, I'll let you solve it. \n" ); document.write( "

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