document.write( "Question 388736: √5/√3 + √(3)/√(5) + 3/5*√(3)/√(5)+... this is limitless sequence Sn is required \n" ); document.write( "
Algebra.Com's Answer #275124 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%285%29%2Fsqrt%283%29\"\"%22%22%2B%22%22\"\"sqrt%283%29%2Fsqrt%285%29\"\"%22%22%2B%22%22\"\"expr%283%2F5%29expr%28sqrt%283%29%2Fsqrt%285%29%29\"
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document.write( "We check to see if it is a geometric series:\r\n" );
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document.write( "Dividing the second term by the first term:\r\n" );
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document.write( "\"sqrt%283%29%2Fsqrt%285%29\"\"%22%F7%22\"\"sqrt%285%29%2Fsqrt%283%29\"\"%22%22=%22%22\"\"sqrt%283%29%2Fsqrt%285%29\"\"%22%22%2A%22%22\"\"sqrt%283%29%2Fsqrt%285%29\"\"%22%22=%22%22\"\"3%2F5\"\r\n" );
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document.write( "Dividing the third term by the second term:\r\n" );
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document.write( "\"expr%283%2F5%29expr%28sqrt%283%29%2Fsqrt%285%29%29\"\"%22%F7%22\"\"sqrt%283%29%2Fsqrt%285%29\"\"%22%22=%22%22\"\"expr%283%2F5%29expr%28sqrt%283%29%2Fsqrt%285%29%29\"\"%22%22%2A%22%22\"\"sqrt%285%29%2Fsqrt%283%29\"\"%22%22=%22%22\"\"expr%283%2F5%29expr%28cross%28sqrt%283%29%29%2Fcross%28sqrt%285%29%29%29\"\"%22%22%2A%22%22\"\"cross%28sqrt%285%29%29%2Fcross%28sqrt%283%29%29\"\"%22%22=%22%22\"\"3%2F5\"\r\n" );
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document.write( "Since we got the same thing both times, it's a geometric series\r\n" );
document.write( "and the common ratio is what we got, namely \"3%2F5\"\r\n" );
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document.write( "The formula for the infinite sum is:\r\n" );
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document.write( "\"S%5Binfinity%5D\"\"%22%22=%22%22\"\"a%5B1%5D%2F%281-r%29\"\r\n" );
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document.write( "where \"a%5B1%5D=sqrt%285%29%2Fsqrt%283%29\"\r\n" );
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document.write( "Let's rationalize the denominator of that\r\n" );
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document.write( "and \"r=3%2F5\". Substituting:\r\n" );
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document.write( "\"S%5Binfinity%5D\"\"%22%22=%22%22\"\"expr%28sqrt%2815%29%2F3%29%2F%281-3%2F5%29\"\"%22%22=%22%22\"\"expr%28sqrt%2815%29%2F3%29%2F%282%2F5%29\"\"%22%22=%22%22\"\"expr%28sqrt%2815%29%2F3%29%2Aexpr%285%2F2%29\"\"%22%22=%22%22\"\"5sqrt%2815%29%2F6\"\r\n" );
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document.write( "Edwin
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