document.write( "Question 388734: A box contains 15 yellow, 29 green and 36 red jelly beans.
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Algebra.Com's Answer #275122 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
A box contains 15 yellow, 29 green and 36 red jelly beans.
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document.write( "That's (15 yellows, choose 6) AND (29+36=65 non-yellows choose 4)\r\n" );
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document.write( "out of\r\n" );
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document.write( "(15+29+36=80 jelly beans choose 10)\r\n" );
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document.write( "That's  \"%2815C6%2A65C4%29%2F%2880C10%29\" or .0020580634 \r\n" );
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\n" ); document.write( "b) 6 are yellow and 3 are green?
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document.write( "That's (15 yellows, choose 6) AND (29 greens choose 3) AND (36 reds choose 1)\r\n" );
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document.write( "out of\r\n" );
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document.write( "(15+29+36=80 jelly beans choose 10)\r\n" );
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document.write( "That's  \"%2815C6%2A29C3%2A36C1%29%2F%2880C10%29\" or .0003998668146\r\n" );
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\n" ); document.write( "\n" ); document.write( "c) At least one is yellow?
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document.write( "This is much easier to do by first finding the probability of the\r\n" );
document.write( "complement event and then subtracting from 1\r\n" );
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document.write( "The complement event is to choose all non-yellows, that is, \r\n" );
document.write( "only greens and reds.\r\n" );
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document.write( "That's 29+36=65 non-yellows, choose 10\r\n" );
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document.write( "out of\r\n" );
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document.write( "(15+29+36=80 jelly beans choose 10)\r\n" );
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document.write( "That's \"%2865C10%29%2F%2880C10%29\" or .10872439\r\n" );
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document.write( "But that's the probability of the complement event.\r\n" );
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document.write( "The probability that you want is 1 - .10872439 or .891275641\r\n" );
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document.write( "Edwin
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