document.write( "Question 388733: A container with a square base, vertical sides,
\n" ); document.write( "and open top is to be made from 1000 ft2 of material.
\n" ); document.write( "(a) Write an equation for the volume of the con-
\n" ); document.write( "tainer as a function of the length of a side of
\n" ); document.write( "the base.
\n" ); document.write( "(b) Write an equation for the volume of the con-
\n" ); document.write( "tainer as a function of the length of the ver-
\n" ); document.write( "tical side\r
\n" ); document.write( "\n" ); document.write( "I can do part (a) but I am stuck on (b), Help would be greatly appreciated. Thanks
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Algebra.Com's Answer #275099 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
(a)
\n" ); document.write( "The square base can be any size, so I'll call
\n" ); document.write( "the sides of the base \"x\".
\n" ); document.write( "I want the \"1000\" ft2 of material to be a
\n" ); document.write( "square also, so the sides of the container will
\n" ); document.write( "all be the same height .
\n" ); document.write( "that means each side of the material will be
\n" ); document.write( "\"10%2Asqrt%2810%29\" ft2
\n" ); document.write( "I'll place the \"x%5E2\" ft2 base exactly in the center.
\n" ); document.write( "That means the 4 sides will measure \"x\" by \"%2810%2Asqrt%2810%29+-+x%29%2F2\"
\n" ); document.write( "Let \"V\" = volume
\n" ); document.write( "\"V+=+x%5E2%2A%2810%2Asqrt%2810%29+-+x%29%2F2\"
\n" ); document.write( "\"V+=+5%2Asqrt%2810%29%2Ax%5E2+-+x%5E3%2F2\"
\n" ); document.write( "Is this what you got?
\n" ); document.write( "(b)
\n" ); document.write( "I'll call the length of the vertical side \"y\"
\n" ); document.write( "\"y+=+%2810%2Asqrt%2810%29+-+x%29%2F2\"
\n" ); document.write( "Ok, now I can say that
\n" ); document.write( "\"V+=+x%5E2%2Ay\"
\n" ); document.write( "Now I just have to find \"x\" in terms of \"y\",
\n" ); document.write( "so I go back to \"y+=+%2810%2Asqrt%2810%29+-+x%29%2F2\"
\n" ); document.write( "\"2y+=++10%2Asqrt%2810%29+-+x\"
\n" ); document.write( "\"x+=+10%2Asqrt%2810%29+-+2y\"
\n" ); document.write( "Now I can say
\n" ); document.write( "\"V+=+%2810%2Asqrt%2810%29+-+2y%29%5E2+%2Ay\"
\n" ); document.write( "\"V+=+%281000+-+40%2Asqrt%2810%29%2Ay+%2B+4y%5E2%29%2Ay\"
\n" ); document.write( "\"V+=+4y%5E3+-+40%2Asqrt%2810%29%2Ay%5E2+%2B+1000y\"
\n" ); document.write( "Check answer:
\n" ); document.write( "Suppose \"y+=+1\"
\n" ); document.write( "That would mean \"x+=+10%2Asqrt%2810%29+-+2\"
\n" ); document.write( "\"V+=+1%2A%281000+-+40%2Asqrt%2810%29%29+%2B+4\"
\n" ); document.write( "\"V+=+1004+-+40%2Asqrt%2810%29\"
\n" ); document.write( "The equation gives me:
\n" ); document.write( "\"V+=+4y%5E3+-+40%2Asqrt%2810%29%2Ay%5E2+%2B+1000y\"
\n" ); document.write( "\"V+=+4+-+40%2Asqrt%2810%29+%2B+1000\"
\n" ); document.write( "same answer
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