document.write( "Question 388620: 4 A recurrance relationship is such that Un+1=a/4Un+12.
\n" ); document.write( "4(a).If U0=16 show clearly that U2=aČ+3a+12
\n" ); document.write( "4(b).Hence find a if U2=30 and a>0\r
\n" ); document.write( "\n" ); document.write( "Can you provide full working with solution.\r
\n" ); document.write( "\n" ); document.write( "Many Thanks,
\n" ); document.write( "Andy
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Algebra.Com's Answer #275060 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"U_%28n%2B1%29+=+%28a%2F4%29U_n+%2B+12\"
\n" ); document.write( "a. U_0 = 16 ===> \"U_1+=+%28a%2F4%29%2A16+%2B+12+=+4a+%2B+12\". Then
\n" ); document.write( "\"U_2+=+%28a%2F4%29%2A%284a%2B12%29+%2B+12+=+a%28a%2B3%29%2B12+=+a%5E2+%2B+3a+%2B+12\".\r
\n" ); document.write( "\n" ); document.write( "b.If \"U_2+=+30+=+a%5E2+%2B+3a+%2B+12\", then \"a%5E2+%2B+3a+-18+=+0\", and (a+6)(a-3) = 0. Therefore a = 3. (Eliminate -6 because we want a>0).
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