document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388649>Question 388649</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4. A cyclist goes from one village to another at 28 km/h. he returns at 24 km/h. if the return journey takes two hours longer than the outward journey. What is the distance between the villages? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275040 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance = speed x time\r<BR>\n" );
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document.write( "let x = hours for outward journey<BR>\n" );
document.write( " (x+2) = hours for return trip (as stated in problem)\r<BR>\n" );
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document.write( "28x =24(x+2)\r<BR>\n" );
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document.write( "28x = 24x + 48\r<BR>\n" );
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document.write( "28x - 24x = 48\r<BR>\n" );
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document.write( "4x = 48\r<BR>\n" );
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document.write( "x = 12 hours\r<BR>\n" );
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document.write( "12 hours times 28 km/hr = 336 km\r<BR>\n" );
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document.write( "ans: distance between villages is 336 kilometers </SPAN>\n" );
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