document.write( "Question 388668: A rectangle is to be drawn with perimeter 64cm. if the length is to be 14cm more than the width, determine the area of the rectangle \n" ); document.write( "
Algebra.Com's Answer #275029 by jim_thompson5910(35256)\"\" \"About 
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The perimeter for a rectangle is \"2L%2B2W=P\" where L is the length and W is the width. Since \"A rectangle is to be drawn with perimeter 64cm\", we know that P=64, which means that \"2L%2B2W=64\"\r
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\n" ); document.write( "\n" ); document.write( "Also since \"the length is to be 14cm more than the width\", we can say that \"L=W%2B14\"\r
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\n" ); document.write( "\n" ); document.write( "So plug this into \"2L%2B2W=64\" to get \"2%28W%2B14%29%2B2W=64\"\r
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\n" ); document.write( "\n" ); document.write( "\"2W%2B28%2B2W=64\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"28%2B4W=64\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"4W=64-28\" Subtract \"28\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"4W=36\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"W=%2836%29%2F%284%29\" Divide both sides by \"4\" to isolate \"W\".\r
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\n" ); document.write( "\n" ); document.write( "\"W=9\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Since \"L=W%2B14\" and \"W=9\", this means that \"L=9%2B14=23\"\r
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\n" ); document.write( "\n" ); document.write( "So \"L=23\"\r
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\n" ); document.write( "\n" ); document.write( "So the length is 23 and the width is 9. This means that the area is \"A=LW=23%2A9=207\"\r
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\n" ); document.write( "\n" ); document.write( "So the area is 207 square cm.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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