document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388646>Question 388646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> </i>I've been having some problems acquiring a formula for finding how much of an object is submerged in water. I have an object that is 10 cm wide, 10 cm, and 4 cm high. Its density is 1.000 g/cm<sup>3</sup>.<br /> It is being placed in salt water, which has a density of 1.025 g/cm<sup>3</sup>. So I guess what I'm asking is for a formula that will solve for <b>s</b>. I know that if I use a number substituting s, for example .50 <br />(%50 submerged) that that will give me a buoyancy force of 205g. I'm trying to figure out how far the object will be submerged before the buoyancy force is equal to mass of the object.\r<BR>\n" );
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document.write( "B = p<sub>f</sub>V<sub>o</sub>s\r<BR>\n" );
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document.write( "Where <BR>\n" );
document.write( "<b>B</b> is buoyancy force.<BR>\n" );
document.write( "<b>p<sub>f</sub></b> is the density of the liquid the object is being placed in.<BR>\n" );
document.write( "<b>V<sub>o</sub></b> is the volume of the object.<BR>\n" );
document.write( "<b>s</b> is the percent of the object submerged in the liquid.\r<BR>\n" );
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document.write( "<b>p<sub>f</sub></b> = 1.025 g/cm<sup>3</sup><BR>\n" );
document.write( "<b>V<sub>o</sub></b> = 400 cm<sup>3</sup> </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #275009 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=275009\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have an object that is 10 cm wide, 10 cm, and 4 cm high. Its density is 1.000 g/cm<sup>3</sup>.<br /> It is being placed in salt water, which has a density of 1.025 g/cm<sup>3</sup>. So I guess what I'm asking is for a formula that will solve for <b>s</b>. I know that if I use a number substituting s, for example .50 <br />(%50 submerged) that that will give me a buoyancy force of 205g. I'm trying to figure out how far the object will be submerged before the buoyancy force is equal to mass of the object.<BR>\n" );
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document.write( "The object have a volume of 400 cc, so it weighs 400 grams.<BR>\n" );
document.write( "It will displace 400 grams of water.<BR>\n" );
document.write( "400/1.025 = 390.24 cc<BR>\n" );
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document.write( "You say it's 4 cm high, implying that the 4 cm is the vertical dimension.  If it's submerged in that orientation, its depth will be 390.24/100 cm<BR>\n" );
document.write( "=~ 3.9 cm submerged.<BR>\n" );
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