document.write( "Question 388617: 2. Two functions are defined on suitable domains as f(x)=4x+1 and g(x)=1/x-1. \r
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document.write( "If h(x) = f(g(x)), show clearly that h(x) can be written as h(x)=x+3/1-x.\r
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document.write( "Can you please provide solutions with full answers please. \r
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document.write( "Many Thanks,
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document.write( "Andy.\r
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Algebra.Com's Answer #275002 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Two functions are defined on suitable domains as f(x)=4x+1 and g(x)=1/(x-1). \n" ); document.write( "If h(x) = f(g(x)), show clearly that h(x) can be written as h(x)=x+3/1-x. \n" ); document.write( "--- \n" ); document.write( "h(x) = f(g(x)) = f[1/(x-1)] = 4[1/(x-1)]+1 = [4/(x-1)] + 1 \n" ); document.write( "---- \n" ); document.write( "= [4 + (x-1]/(x-1 \n" ); document.write( "= (3+x)/(x-1) \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--- \n" ); document.write( " \n" ); document.write( " |