document.write( "Question 388617: 2. Two functions are defined on suitable domains as f(x)=4x+1 and g(x)=1/x-1. \r
\n" ); document.write( "\n" ); document.write( "If h(x) = f(g(x)), show clearly that h(x) can be written as h(x)=x+3/1-x.\r
\n" ); document.write( "\n" ); document.write( "Can you please provide solutions with full answers please. \r
\n" ); document.write( "\n" ); document.write( "Many Thanks,
\n" ); document.write( "Andy.\r
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Algebra.Com's Answer #275002 by stanbon(75887)\"\" \"About 
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Two functions are defined on suitable domains as f(x)=4x+1 and g(x)=1/(x-1).
\n" ); document.write( "If h(x) = f(g(x)), show clearly that h(x) can be written as h(x)=x+3/1-x.
\n" ); document.write( "---
\n" ); document.write( "h(x) = f(g(x)) = f[1/(x-1)] = 4[1/(x-1)]+1 = [4/(x-1)] + 1
\n" ); document.write( "----
\n" ); document.write( "= [4 + (x-1]/(x-1
\n" ); document.write( "= (3+x)/(x-1)
\n" ); document.write( "===============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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