document.write( "Question 388618: 1. Solve algebraically the equation 15sin2x°=10cosx° for 0≤x<360.
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Algebra.Com's Answer #275001 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve algebraically the equation \n" ); document.write( "15sin(2x)°=10cos(x)° for 0≤x<360. \n" ); document.write( "--- \n" ); document.write( "sin(2x)/cos(x) = 2/3 \n" ); document.write( "---- \n" ); document.write( "(2sin(x)(cos(x))/cos(x) = 2/3 \n" ); document.write( "---- \n" ); document.write( "2sin(x) = 2/3 \n" ); document.write( "--- \n" ); document.write( "sin(x) = (1/3) \n" ); document.write( "--- \n" ); document.write( "x = sin^1(1/3) = 19.47 degrees or 180-19.47 = 160.53 degrees \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |