document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388643>Question 388643</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need your help please!<BR>\n" );
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document.write( "If tan &#952; = -2/3 and angle &#952; lies in the second quadrant, what is the value of cos &#952;?\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274993 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If tan &#952; = -2/3 and angle &#952; lies in the second quadrant, what is the value of cos &#952;?<BR>\n" );
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document.write( "tan(theta) = y/x and x is negative in the second quadrant.<BR>\n" );
document.write( "Therefore y = 2 and x = -3<BR>\n" );
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document.write( "To get the cos(theta) you need to know \"r\":<BR>\n" );
document.write( "r = sqrt(2^2+3^2) = sqrt(13)<BR>\n" );
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document.write( "So, cos(theta) = x/r = -3/sqrt(13)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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