document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388638>Question 388638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2 passenger trains traveling in opposite directions meet and pass each other. Each train is 1/12 mi long and is traveling at 50 mph. How many seconds after front part of the trains meet will their rear parts pass each other? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274989 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 passenger trains traveling in opposite directions meet and pass each other. Each train is 1/12 mi long and is traveling at 50 mph. How many seconds after front part of the trains meet will their rear parts pass each other?\r<BR>\n" );
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document.write( "1/12 mile * 5280 feet/mile = 440 feet per train<BR>\n" );
document.write( "50 miles/hour * 1/3600 hr/sec * 5280 ft/mile = 73 1/3 ft/second<BR>\n" );
document.write( "one train has to travel 440 feet to pass the other train<BR>\n" );
document.write( "440 feet * 1/(73 1/3) sec/ft = 6 seconds<BR>\n" );
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