document.write( "Question 388619: 1. Solve algebraically the equation 15sin2x°=10cosx° for 0≤x<360\r
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document.write( "Can you provide full working.\r
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document.write( "Andy. \n" );
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Algebra.Com's Answer #274985 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! 15 sin 2x = 10 cos x. By double-angle formula, sin 2x = 2 sin x cos x, so\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "30 sin x cos x = 10 cos x. Move 10 cos x to the other side and divide by 10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 sin x cos x - cos x = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cos x (3 sin x - 1) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cos x = 0 or sin x = 1/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 90, 270, or x = arcsin (1/3) \n" ); document.write( " |