document.write( "Question 388619: 1. Solve algebraically the equation 15sin2x°=10cosx° for 0≤x<360\r
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Algebra.Com's Answer #274985 by richard1234(7193)\"\" \"About 
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15 sin 2x = 10 cos x. By double-angle formula, sin 2x = 2 sin x cos x, so\r
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\n" ); document.write( "\n" ); document.write( "30 sin x cos x = 10 cos x. Move 10 cos x to the other side and divide by 10\r
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\n" ); document.write( "\n" ); document.write( "3 sin x cos x - cos x = 0\r
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\n" ); document.write( "\n" ); document.write( "cos x (3 sin x - 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "cos x = 0 or sin x = 1/3\r
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\n" ); document.write( "\n" ); document.write( "x = 90, 270, or x = arcsin (1/3)
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