document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388231>Question 388231</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help!\r<BR>\n" );
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document.write( "4% of Americans surveyed lie frequently. Suppose you conduct a survey of 450 college students and find that 22 of them lie frequently. Compute the probability that, in a random sample of 450 students, at least 22 lie frequently, assuming the true percentage is 4%.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274967 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274967\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the normal approximation to the binomial distribution, with <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=mu+=+np+=+450%2A0.04+=+18 ALIGN=MIDDLE  ALT=\"mu+=+np+=+450%2A0.04+=+18\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sigma+=+sqrt%28npq%29+=+sqrt+%28450%2A0.04%2A0.96%29+=+4.156922 ALIGN=MIDDLE  ALT=\"sigma+=+sqrt%28npq%29+=+sqrt+%28450%2A0.04%2A0.96%29+=+4.156922\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Then<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P%28X+%3E=+21.5%29+=+P%28%28X+-+mu%29%2Fsigma+=+%28X+-+18%29%2F4.156922+%3E=+%2821.5+-+18%29%2F4.156922+=+0.842%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >.  Hence <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P%28X+%3E=+21.5%29+=+P%28Z+%3E=+0.842%29 ALIGN=MIDDLE  ALT=\"P%28X+%3E=+21.5%29+=+P%28Z+%3E=+0.842%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Now just use any standard normal distribution table to find <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P%28Z+%3E=+0.842%29 ALIGN=MIDDLE  ALT=\"P%28Z+%3E=+0.842%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and hence the answer you want. </SPAN>\n" );
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