document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388609>Question 388609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a garrison of 1600 men is provisioned for 18 weeks at the rate of 25 kg per day per man.if some more persons join the garrison, the provisions would last for 16 weeks at the rate of 20 kg per day per man. find the number of persons joining the garrison. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274961 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274961\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m1=1600: w1=18: k1=25<BR>\n" );
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document.write( "m2=x:     w2=16: k2=20<BR>\n" );
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document.write( "m2= 1600*(18/16)*(25/20)<BR>\n" );
document.write( "m2= 2250<BR>\n" );
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document.write( "2250-1600 = 650 men joined the garrison<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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