document.write( "Question 388589: A and B are 30 km apart.If they leave at the same time and travel in the same direction, A overtakes B in
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document.write( "60 hours.If they walk toward each other, they meet in 5 hours. What are their rates? \n" );
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Algebra.Com's Answer #274943 by mananth(16946) You can put this solution on YOUR website! A and B are 30 km apart.If they leave at the same time and travel in the same direction, A overtakes B in \n" ); document.write( "60 hours.If they walk toward each other, they meet in 5 hours. What are their rates? \n" ); document.write( "... \n" ); document.write( "A rate = x km/h \n" ); document.write( "B rate y km/h \n" ); document.write( "... \n" ); document.write( "distance 30 km. \n" ); document.write( "... \n" ); document.write( "same direction \n" ); document.write( "-------------- \n" ); document.write( "catch up rate = x-y kmph \n" ); document.write( "catch up time = 60 hours \n" ); document.write( "30/(x-y)=60 \n" ); document.write( "30=60(x-y) \n" ); document.write( "divide by 30 \n" ); document.write( "1=2x-2y....................1 \n" ); document.write( "... \n" ); document.write( "Opposite direction \n" ); document.write( "------------------ \n" ); document.write( "speed = x+y \n" ); document.write( "distance = 30 km \n" ); document.write( "time = 5 hours \n" ); document.write( "30/(x+y)=5 \n" ); document.write( "30=5(x+y0 \n" ); document.write( "/5 \n" ); document.write( "6=x+y.......................2 \n" ); document.write( "multiply (2) by 2 \n" ); document.write( "12=2x+2y \n" ); document.write( "add this to (10 \n" ); document.write( "1+12=2x+2x+2y-2y \n" ); document.write( "13=4x \n" ); document.write( "/4 \n" ); document.write( "13/4 = x \n" ); document.write( " \n" ); document.write( "plug x in (20 \n" ); document.write( "x+y=6 \n" ); document.write( "13/4 + y =6 \n" ); document.write( "y = 6-13/4 \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |