document.write( "Question 388589: A and B are 30 km apart.If they leave at the same time and travel in the same direction, A overtakes B in
\n" ); document.write( "60 hours.If they walk toward each other, they meet in 5 hours. What are their rates?
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Algebra.Com's Answer #274943 by mananth(16946)\"\" \"About 
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A and B are 30 km apart.If they leave at the same time and travel in the same direction, A overtakes B in
\n" ); document.write( "60 hours.If they walk toward each other, they meet in 5 hours. What are their rates?
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\n" ); document.write( "A rate = x km/h
\n" ); document.write( "B rate y km/h
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\n" ); document.write( "distance 30 km.
\n" ); document.write( "...
\n" ); document.write( "same direction
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\n" ); document.write( "catch up rate = x-y kmph
\n" ); document.write( "catch up time = 60 hours
\n" ); document.write( "30/(x-y)=60
\n" ); document.write( "30=60(x-y)
\n" ); document.write( "divide by 30
\n" ); document.write( "1=2x-2y....................1
\n" ); document.write( "...
\n" ); document.write( "Opposite direction
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\n" ); document.write( "speed = x+y
\n" ); document.write( "distance = 30 km
\n" ); document.write( "time = 5 hours
\n" ); document.write( "30/(x+y)=5
\n" ); document.write( "30=5(x+y0
\n" ); document.write( "/5
\n" ); document.write( "6=x+y.......................2
\n" ); document.write( "multiply (2) by 2
\n" ); document.write( "12=2x+2y
\n" ); document.write( "add this to (10
\n" ); document.write( "1+12=2x+2x+2y-2y
\n" ); document.write( "13=4x
\n" ); document.write( "/4
\n" ); document.write( "13/4 = x
\n" ); document.write( "\"%28highlight%28x=+13%2F4%29%29\" speed of A
\n" ); document.write( "plug x in (20
\n" ); document.write( "x+y=6
\n" ); document.write( "13/4 + y =6
\n" ); document.write( "y = 6-13/4
\n" ); document.write( "\"%28highlight%28y=11%2F4%29%29\" speed of B\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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