document.write( "Question 388572: I need help with the perimeter of a rectangle is 174 inches. The length exceeds the width 37 inches. Find the ninth at the width. \n" ); document.write( "
Algebra.Com's Answer #274904 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "We can set up the equation as:
\n" ); document.write( "x represent the width
\n" ); document.write( "x+37 is the length so:
\n" ); document.write( "2x+2(x+37)=174
\n" ); document.write( "Combine like terms:
\n" ); document.write( "4x+74=174
\n" ); document.write( "Subtract 74 from both sides and divide by 4 to get:
\n" ); document.write( "x=25
\n" ); document.write( "There we go the width is 25 inches and the length is 62 inches.
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com
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