document.write( "Question 388572: I need help with the perimeter of a rectangle is 174 inches. The length exceeds the width 37 inches. Find the ninth at the width. \n" ); document.write( "
Algebra.Com's Answer #274904 by unlockmath(1688)![]() ![]() You can put this solution on YOUR website! Hello, \n" ); document.write( "We can set up the equation as: \n" ); document.write( "x represent the width \n" ); document.write( "x+37 is the length so: \n" ); document.write( "2x+2(x+37)=174 \n" ); document.write( "Combine like terms: \n" ); document.write( "4x+74=174 \n" ); document.write( "Subtract 74 from both sides and divide by 4 to get: \n" ); document.write( "x=25 \n" ); document.write( "There we go the width is 25 inches and the length is 62 inches. \n" ); document.write( "Make sense? \n" ); document.write( "RJ \n" ); document.write( "www.math-unlock.com \n" ); document.write( " |