document.write( "Question 5355: I need to use long division to divide
\n" ); document.write( "(2x^2 + x - 13) by (x + 3)
\n" ); document.write( "Thanks for your help
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Algebra.Com's Answer #2749 by Abbey(339)\"\" \"About 
You can put this solution on YOUR website!
Set this up like a long division problem\r
\n" ); document.write( "\n" ); document.write( "(I am going to use the square root sign on the computer)\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B3%29+sqrt%282x%5E2%2Bx-13%29\"
\n" ); document.write( "The steps for long division are:
\n" ); document.write( "Step 1. divide the first term of the numerator by the first term of the denominator
\n" ); document.write( "Step 2. multiply both terms in the denominator by the result of step 1.
\n" ); document.write( "Step 3. subtract the result of step 2 from the original numerator
\n" ); document.write( "Step 4. Bring the next number from the numerator down and add to the result of step 3\r
\n" ); document.write( "\n" ); document.write( "repeat the process \r
\n" ); document.write( "\n" ); document.write( "perform the division part of the long division on the FIRST term of the numerator (the \"2x%5E2\" in the \"%282x%5E2%2Bx-13%29\" and the first term of the denominator (the X in the (x+3)) , but perform the multiplication and subtraction on BOTH terms in the denominator (both the x and the 3 in the (x+3) term):\r
\n" ); document.write( "\n" ); document.write( "Step 1. divide \"2x%5E2\" by x and get 2x
\n" ); document.write( "Step 2. multiply (x+3) by 2x to get \"2x%5E2%2B6x\"
\n" ); document.write( "Step 3. subtract \"2x%5E2%2B6x\" from \"2x%5E2%2Bx-13\" and get \"-5x\"
\n" ); document.write( "Step 4. Bring down the next term \"-13\" and add it to \"-5x\" to get \"-5x-13\"\r
\n" ); document.write( "\n" ); document.write( "Repeat:\r
\n" ); document.write( "\n" ); document.write( "Step 1. divide \"-5x\" by \"x\" to get \"-5\"
\n" ); document.write( "Step 2. multiply \"-+5\" by \"x%2B3\" to get \"-5x-15\"
\n" ); document.write( "Step 3. subtract \"-5x-15\" from \"-5x-13\" and get 2 as a remainder\r
\n" ); document.write( "\n" ); document.write( "The answer will is \"2x-5\" with a remainder of \"2%2F%28x%2B3%29\"\r
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