document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388514>Question 388514</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A farmer is trying to develop a feed mixture consisting of hay and grain. how many tons of hay at $110 per ton and how many tons of grain at $60 must be mixed to produce 100 tons of feed to sell at $70 per ton? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274854 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274854\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = tons of grain at $60/ton<BR>\n" );
document.write( "(100-x)= tons of hay at $110/ton<BR>\n" );
document.write( "mixing grain and hay to produce 100 tons at $70/ton<BR>\n" );
document.write( "=60x+110(100-x)=70(100)=7000<BR>\n" );
document.write( "=60x+11000-110x=7000<BR>\n" );
document.write( "50x=4000<BR>\n" );
document.write( "x=4000/50=80<BR>\n" );
document.write( "100-x=100-80=20<BR>\n" );
document.write( "ans: 80 tons of grain at $60/ton mixed with 20 tons of hay at $110/ton would sell 100 tons of feed at $70/ton<BR>\n" );
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